If $$n(A)=4,n(B)=3,n(A\times B\times C)=24$$, then $$n(C)=$$

Solution

$$n(A)=4$$
$$n(B)=3$$
$$n(A\times B\times C)=24$$
$$n(C)=\cfrac { 24 }{ 4\times 3 } =2$$