If the point $$(2K-3,K+2)$$ lies on the graph of equation $$2x+3x+15=0$$, find the value of x.

Solution

Given point $$(2K-3,K+2)$$
$$2x+3y+15=0$$
$$2(2K-3)+3(K+2)+15=0$$
$$4K-6+3K+6+15=0$$
$$7K+15=0$$
$$K=-15/7$$