If the point $(2K-3,K+2)$ lies on the graph of equation $2x+3x+15=0$, find the value of x.

#### Solution

Given point $(2K-3,K+2)$
$2x+3y+15=0$
$2(2K-3)+3(K+2)+15=0$
$4K-6+3K+6+15=0$
$7K+15=0$
$K=-15/7$