The value of $$\sin ( 360^o - \theta)  $$ is
  • A
    $$-\sin \theta$$
  • B
    $$- \cos \theta $$
  • C
    $$\cos \theta $$
  • D
    $$\sin \theta$$

Solution

$$sin\left ( 360^{\circ}-\theta \right )=?$$

Angle $$360^{\circ}-\theta $$  will lie in fourth quadrant, in which function $$sinx$$ has negative value.

So, $$sin\left ( 360^{\circ}-\theta \right )=-sin\theta $$