The value of $\sin ( 360^o - \theta)$ is
• A
$-\sin \theta$
• B
$- \cos \theta$
• C
$\cos \theta$
• D
$\sin \theta$

#### Solution

$sin\left ( 360^{\circ}-\theta \right )=?$

Angle $360^{\circ}-\theta$  will lie in fourth quadrant, in which function $sinx$ has negative value.

So, $sin\left ( 360^{\circ}-\theta \right )=-sin\theta$