Simplify $$\dfrac{x}{{\sqrt {x + 4} }},\,\,x > 0$$

Solution

given $$\dfrac{x}{\sqrt{x+4}}$$
rationalize above 
$$\dfrac{\dfrac{x}{\sqrt{x+4}}}{\dfrac{\sqrt{x+4}}{\sqrt{x+4}}}$$

$$=\dfrac{x\sqrt{x+4}}{x+4}$$