$\dfrac { 5+2i }{ 1-i } +\dfrac { 5-2i }{ 1+i }$

Solution

$\dfrac { 5+2i }{ 1-i } +\dfrac { 5-2i }{ 1+i } =a+ib$
$\Rightarrow \dfrac { 5+5i+2i-2+5-5i-2i-2 }{ 1+1 } =a+ib$
$\Rightarrow \dfrac{6}{2}=a+bi$
$\Rightarrow 3=a+bi$
$\Rightarrow a=3,$  $b=0$
Hence, the answer is $a=3, b=0.$