$$\dfrac { 5+2i }{ 1-i } +\dfrac { 5-2i }{ 1+i } $$

Solution

$$\dfrac { 5+2i }{ 1-i } +\dfrac { 5-2i }{ 1+i } =a+ib$$
$$\Rightarrow \dfrac { 5+5i+2i-2+5-5i-2i-2 }{ 1+1 } =a+ib$$
$$\Rightarrow \dfrac{6}{2}=a+bi$$
$$\Rightarrow 3=a+bi$$
$$\Rightarrow a=3,$$  $$b=0$$
Hence, the answer is $$a=3, b=0.$$