### Differential Equations

goals
If $\cos\ y=x \cos(a+y)$ then prove that:
$\dfrac{dy}{dx}=\dfrac{\cos^{2}(a+y)}{\sin a}$
The solution of $ydx-xdy+\log {x}dx=0$ is
The solution of $ydx-xdy+\log {x}dx=0$ is
The solution of $ydx-xdy+\log {x}dx=0$ is
The solution of $ydx-xdy+\log {x}dx=0$ is